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If m is different from zero
[#permalink]
07 Sep 2021, 07:03

Expert Reply

Question Stats:

If \(m \neq 0 \)and \(m - \frac{1+2m^2}{2m}=\frac{y}{m}\), then y is =

A. \(-1\)

B. \(- \frac{1}{2}\)

C. \(-(1+4m^2)\)

D. \(- \frac{1+4m^2}{2}\)

E. \((2m+1)^2\)

_________________

A. \(-1\)

B. \(- \frac{1}{2}\)

C. \(-(1+4m^2)\)

D. \(- \frac{1+4m^2}{2}\)

E. \((2m+1)^2\)

_________________

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ETS: ETS Free PowerPrep 1 & 2 All 320 Questions Explanation. | ETS All Official Guides

3rd Party Resource's: All Quant Questions Collection | All Verbal Questions Collection

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Scores: The GRE average score at Top 25 Business Schools 2020 Ed. | How to study for GRE retake and score HIGHER - (2020)

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If m is different from zero
[#permalink]
07 Sep 2021, 08:30

\(m - \frac{1+2m^2}{2m}=\frac{y}{m}\)

Take the LCM

\(2m^2 - 1 - 2m^2 = 2y\)

\(y =\frac{-1}{2}\)

Answer B

_________________

Take the LCM

\(2m^2 - 1 - 2m^2 = 2y\)

\(y =\frac{-1}{2}\)

Answer B

_________________

Want to crush the GRE? One stop SHOP

Re: If m is different from zero
[#permalink]
10 Sep 2021, 07:15

Expert Reply

Carcass wrote:

If \(m \neq 0 \)and \(m - \frac{1+2m^2}{2m}=\frac{y}{m}\), then y is =

A. \(-1\)

B. \(- \frac{1}{2}\)

C. \(-(1+4m^2)\)

D. \(- \frac{1+4m^2}{2}\)

E. \((2m+1)^2\)

A. \(-1\)

B. \(- \frac{1}{2}\)

C. \(-(1+4m^2)\)

D. \(- \frac{1+4m^2}{2}\)

E. \((2m+1)^2\)

Given: \(m - \frac{1+2m^2}{2m}=\frac{y}{m}\)

To eliminate all fractions, we can multiply both sides of the equation by the least common multiple (LCM) of the denominators (2m and m).

The LCM of 2m and m is 2m, so we will multiply both sides by 2m to get: \(2m^2 - (1+2m^2)=2y\)

Simplify the left side to get: \(-1=2y\)

Divide both sides by 2 to get: to get: \(-\frac{1}{2}=y\)

Answer: B

_________________

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